## Download Contemporary Precalculus: A Graphing Approach by Thomas W. Hungerford, Douglas J. Shaw PDF

By Thomas W. Hungerford, Douglas J. Shaw

Revered for its designated suggestions in utilizing expertise, modern PRECALCULUS: A GRAPHING procedure, 5th variation, is written from the floor as much as be used with graphing calculators that you could be be utilizing on your precalculus path. you will have fun with that the textual content has additionally lengthy been famous for its cautious, thorough motives and its presentation of arithmetic in an off-the-cuff but mathematically special demeanour. The authors additionally emphasize the all-important "why?" of mathematics--which is addressed in either the exposition and within the workout units via targeting algebraic, graphical, and numerical views.

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**Additional info for Contemporary Precalculus: A Graphing Approach**

**Example text**

6x Ϫ 9Ȋ ϭ 0 4. Ȋ4x Ϫ 5Ȋ ϭ Ϫ9 5. Ȋ2x ϩ 3Ȋ ϭ 4x Ϫ 1 6. Ȋ3x Ϫ 2Ȋ ϭ 5x ϩ 4 7. Ȋx Ϫ 3Ȋ ϭ x 8. Ȋ2x Ϫ1Ȋ ϭ 2x ϩ 1 9. Ȋx ϩ 4x Ϫ 1Ȋ ϭ 4 2 11. B 10. Ȋx ϩ 2x Ϫ 9Ȋ ϭ 6 2 12. Ȋ12x 2 ϩ 5x Ϫ 7Ȋ ϭ 4 SPECIAL TOPICS Section Objectives 13. In statistical quality control, one needs to find the propor- tion of the product that is not acceptable. The upper and lower control limits are found by solving the following equation (in which ෆp is the mean percent defective and n is the sample size) for CL. 02 and n ϭ 200. Variation ■ Set up and solve a direct variation equation.

7 meters ȊϪ5Ȋ ϪȊ4Ȋ ȊϪ1Ȋ 80. 5 ȊϪ2Ȋ 82. ȊϪ3Ȋ 84. ϪȊϪ4Ȋ 0 0 In Exercises 85–92, find the distance between the given numbers. 52. 00000000001 meter 53. 000000002 meter 85. Ϫ3 and 4 86. 7 and 107 In Exercises 54–57, express the given number in normal decimal notation. 87. Ϫ7 and 15/2 88. Ϫ3/4 and Ϫ10 89. p and 3 90. p and Ϫ3 54. 9979 ϫ 108 miles per second 91. ͙2 ෆ and ͙3ෆ 92. p and ͙2 ෆ 55. 50 ϫ 10 meters 93. Galileo discovered that the period of a pendulum depends 11 56. 602 ϫ 10Ϫ27 coulomb 57. 6726 ϫ 10 Ϫ19 kilogram 58.

Use this fact and the equation in part (b) to obtain the formula used in Example 4. In Exercises 97–99, find the absolute value of the difference of the two given wind-chill factors. For example, the difference between the wind-chill at 30°with a 15 mph wind and one at Ϫ10°with a 10 mph wind is Ȋ19Ϫ(Ϫ28)Ȋ ϭ 47° or, equivalently, ȊϪ28 Ϫ 19Ȋ ϭ 47°. 97. 10° with a 25 mph wind and 20° with a 20 mph wind 98. 30° with a 10 mph wind and 10° with a 30 mph wind 99. Ϫ30° with a 5 mph wind and 0° with a 10 mph wind 95.